Back
• Assignment Services
• Engineering
• Mechanical
• Basic Subjects
• Law
• Management
• Accounting and Finance
• Programming
• Medical
• Humanities
• Essay
Back
• Writing Services help
Back
• Dissertation help
Back
• Assignment by Universities
Back
• Homework help
Back
• Australia
• New Zealand
• United Kingdom
• United States of America
• Malaysia
• United Arab Emirates
• Singapore
• China
• Ireland
Back
• CDR Report

Welcome to Live Chat

Welcome to LiveWebTutors Services, World's leading Academic solutions provider with Millions of Happy Students.

Call Back

24x7 Support Available

chat now

In A Hurry? Get A Callback

Table of Content

# Maxima and Minima

We can use differentiation to find out the maxima and minimum values of the given function. Maxima and minimum values are also known as the critical values of the given function.When the first order derivative of the function that is dy / dx = 0 and the second order derivative of the function that is d^2y / dx^2 is greater than zero then the function is said to have a minimum value.

If the first order derivative of the function that is dy / dx = 0 and second order derivative of the function that is d^2y / dx^2 is less than zero then the function is said to have a maximum value. If the second order derivative of the function that is d^2 y / dx^2 is exactly equal to zero then the function is said to have both minimum or maximum values at one point.

Let us discuss maxima and minima with some of the examples.

Consider the first example be: find out the maxima and minimum values of the given function y = x^3 – 3x + 2.

The given mathematicsfunction is y = x^3 – 3x + 2. Now first let us differentiate the given function then we will get it as dy / dx = dy / dx (x^3 – 3x + 2) which is equal to dy / dx = 3x^2 – 3. Now let us equate the first differentiation to 0 then we will get it as 3x^2 – 3 = 0 in this take 3 as common then we will get it as 3(x^2 – 1) = 0 now take 3 to the left hand side then we will get it as x^2 – 1 = 0 this is in the form of (a)^2 – (b)^2 which is equals to (a + b)(a – b), so now we will get it as (x + 1)(x – 1). Now we will get the x values as 1 and -1. Now let us substitute the given x values in the given function then we will get it as if x = 1 then y = (1)^3 – 3(1) + 2 which is equals to 1 - + 2 = 0. If x = -1 then we will get it as y = (-1)^3 – 3(-1) + 2 which is equals to -1 + 3 + 2 = 4. These are known as stationary points. Now let us find out second order derivative then we will get it as d^2y / dx^2 = 6x. in this if we substitue x = -1 then we will get it as 6(-1) = -6 which is less than 0 so at this point the function has maximum value. If we substitute x = 1 we will get it as 6(1) = 6 which is greater than 0 so at this point the function has minimum value.

Our Amazing Features
• On Time Delivery

There is no deadline that can stop our writers from delivering quality assignments to the students.

• Plagiarism Free Work

Get authentic and unique assignments by using our 100% plagiarism-free services.

• 24 X 7 Live Help

The experienced team of Live web tutors has got your back at all times of the day. Get connected with our customer support executives to receive instant and live solutions for your assignment problems.

• Services For All Subjects

We can build quality assignments in the subjects you're passionate about. Be it Engineering and Literature or Law and Marketing we have an expert writer for all.

• Best Price Guarantee

Get premium service at a pocket-friendly rate. At live web tutors, we understand the tight budget of students and thus offer our services at highly affordable prices.

FREE RESOURCES
FREE SAMPLE FILE
live review Our Mission Client Satisfaction
• I have been supremely impressed with the service acquired. So I am also going to refer it to you, and you can make most of it.

19 Sep 2020

Jason

• My examiners were thoroughly impressed and happy with the assignment I submitted. It was not only enriching, but also extremely resourceful, all thanks to the team of writers.

19 Sep 2020

Samuel

• It was my first time of availing their service, and trust me, I have not been disappointed. Their service has indeed helped me to procure a unique assistance, and I am really happy to hire them.

19 Sep 2020

Jacob

• This is by far the fastest academic service that I received. The team is so proficient that they maintained a superior quality and yet within the deadline as promised.

19 Sep 2020

Stephen

• Searching for the perfect assistance is never an easy task, but with the excellent assistance that I availed, everything became a mere stress free affair. The team took utmost responsibility of my thesis and submitted it in the estimated time.

19 Sep 2020

Sean

View All Review