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## Computers, data and programming

#### Question Preview:

Question 1. a) Determine the value of basebif (152) b= 0x6A. Please show all steps. b) Convert the followings: (Please show all steps; no marks will be awarded if no steps are shown) i) 0xBAD into 3-base representation ii) 321 7 into 2-base (binary) representation iii) 123 5 into an octal representation iv) 21, 21 8 into decimal representation c) Given a (very) tiny computer that has a word size of 3 bits, what are the lowest value (negative numbers) and the highest value (positive number) that this computer can represent in each of the following representations? i) One...

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#### Question Preview:

Question 1. a) Determine the value of basebif (152) b= 0x6A. Please show all steps. b) Convert the followings: (Please show all steps; no marks will be awarded if no steps are shown) i) 0xBAD into 3-base representation ii) 321 7 into 2-base (binary) representation iii) 123 5 into an octal representation iv) 21, 21 8 into decimal representation c) Given a (very) tiny computer that has a word size of 3 bits, what are the lowest value (negative numbers) and the highest value (positive number) that this computer can represent in each of the following representations? i) One's complement ii) Two's complement iii) Signed Magnitude

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## Solution Preview

The maximum value of n for which the program produces the correct result is 23 whose Fibonacci value is 28657. The program does not produce a valid result for 24 because in MARIE Simulator integer can only hold 16-bits of data. A 16-bit integer can store the maximum value of 32767. Fibonacci value of 24 which is 46368 exceeds maximum value the integer can hold. So buffer overflow takes place and the wrong result is generated.

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